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Question
First four terms of an A.P., are ______ whose first term is –2 and the common difference is –2.
Options
– 2, 0, 2, 4
– 2, 4, – 8, 16
– 2, – 4, – 6, – 8
– 2, – 4, – 8, – 16
Solution
First, four terms of an A.P., are – 2, – 4, – 6, – 8 whose first term is –2 and the common difference is –2.
Explanation:
Let the first four terms of an A.P are a, a + d, a + 2d and a + 3d
Given that the first term is – 2 and difference is also – 2, then the A.P would be:
– 2, (– 2 – 2), [– 2 + 2 (– 2)], [– 2 + 3(– 2)]
= – 2, – 4, – 6, – 8
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