Question

For a reaction \[\ce{2A -> 3B}\], rate of reaction `-("d"["A"])/"dt"` is equal to ______.

Options

• `(+3)/2 ("d"["B"])/"dt"`

• `(+2)/3 ("d"["B"])/"dt"`

• `(+1)/3 ("d"["B"])/"dt"`

• `+(2"d"["B"])/"dt"`

Answer 1

For a reaction \[\ce{2A -> 3B}\], rate of reaction `-("d"["A"])/"dt"` is equal to `bbunderline((+2)/3 ("d"["B"])/"dt")`.

Explanation:

Rate of reaction = `(-1)/2 ("d"["A"])/"dt" = (+1)/3 ("d"["B"])/"dt"`

`(-"d"["A"])/"dt" = (+2)/3 ("d"["B"])/"dt"`