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Question
For a binomial distribution mean is 6 and variance is 2. Find n and p.
Solution
Mean = 6, Variance = 2 But,
Mean = np and Variance = npq
∴ np = 6 and npq = 2
npq=2
(6)q=2 [∵ np=6]
q=1/3 ......(1)
p=1-1/3=2/3 [∵p=1-q]
`p=2/3`
np=6
n(2/3)=6
`n=9`
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