Question

For the reaction, \[\ce{2NH3 -> N2 + 3H2}\], if `(-"d" ["NH"_3])/"dt"` = k₁ [NH₃], `("d" ["N"_2])/"dt"` = k₂ [NH₃], `("d" ["H"_2])/"dt"` = k₃ [NH₃] then the relation between k₁, k₂ and k₃ is

Options

• k₁ = k₂ = k₃

• k₁ = 3 k₂ = 2 k₃

• 1.5 k₁ = 3 k₂ = k₃

• 2 k₁ = k₂ = 3 k₃

Answer 1

1.5 k₁ = 3 k₂ = k₃