English

Force acting on a particle is (2ii^ + 3 jj^) N. Work done by this force is zero, when a particle is moved on the line 3y + kx = 5. Here value of k is ______. -

Advertisements
Advertisements

Question

Force acting on a particle is (2`hat"i"` + 3 `hat"j"`) N. Work done by this force is zero, when a particle is moved on the line 3y + kx = 5. Here value of k is ______.

Options

  • 2

  • 4

  • 6

  • 8

MCQ
Fill in the Blanks

Solution

Force acting on a particle is (2`hat"i"` + 3 `hat"j"`) N. Work done by this force is zero, when a particle is moved on the line 3y + kx = 5. Here value of k is 2.

Explanation:

Force is parallel to a line y = `3/2x+"c"`

The equation of given line can be written as

y = `-"k"/3x+5/3`

When force is perpendicular to displacement, i.e. the above two lines are perpendicular, work done is zero or

m1m2 = –1

or `(3/2) (-"k"/3)` = -1

or k = 2

shaalaa.com
  Is there an error in this question or solution?
Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×