हिंदी

Force acting on a particle is (2ii^ + 3 jj^) N. Work done by this force is zero, when a particle is moved on the line 3y + kx = 5. Here value of k is ______. -

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प्रश्न

Force acting on a particle is (2`hat"i"` + 3 `hat"j"`) N. Work done by this force is zero, when a particle is moved on the line 3y + kx = 5. Here value of k is ______.

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उत्तर

Force acting on a particle is (2`hat"i"` + 3 `hat"j"`) N. Work done by this force is zero, when a particle is moved on the line 3y + kx = 5. Here value of k is 2.

Explanation:

Force is parallel to a line y = `3/2x+"c"`

The equation of given line can be written as

y = `-"k"/3x+5/3`

When force is perpendicular to displacement, i.e. the above two lines are perpendicular, work done is zero or

m1m2 = –1

or `(3/2) (-"k"/3)` = -1

or k = 2

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