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Question
From a solid cylinder of height 14 cm and base diameter 7 cm, two equal conical holes each of radius 2.1 cm and height 4 cm are cut off. Find the volume of the remaining solid.
Solution
we have,
the height of the cylinder, H=14 cm,
the base radius of cylinder, R = `7/2 cm `
the base radius of each conical holes, r =2.1 cm and
the height of each conical holes, h=4 cm
volume of the remaining solid = volume of thecylinder- volume of 2 conical holes
`=piR^2H - 2xx1/3pir^2h`
`=22/7xx7/2xx7/2xx14-2/3xx22/7xx2.1xx2.1xx4`
= 539 - 36.96
=502.04 cm3
So, the volume of the remaining solid is 502.04 cm3.
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