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Question
A solid iron pole consists of a cylinder of height 220 cm and base diameter 24 cm, which is surmounted by another cylinder of height 60 cm and radius 8 cm. Find the mass of the pole, given that 1 cm3 of iron has approximately 8 g mass. [Use π = 3.14]
Solution
rom the figure, it can be observed that
Height (h1) of larger cylinder = 220 cm
Radius (r1) of larger cylinder = `24/2` = 12 cm
Height (h2) of smaller cylinder = 60 cm
Radius (r2) of smaller cylinder = 8 cm
Total volume of pole = volume of larger cylinder + volume of smaller cylinder
`= pir_1^2h_1+pir_2^2h_2`
`=pi(12)^2xx220+pi(8)^2xx60`
`=pi[144xx220+64xx60]`
= `35520xx3.14`
= 111532.8 cm3
Mass of 1 cm3 iron = 8 g
Mass of 111532.8 cm3 iron
= 111532.8 × 8
= 892262.4 g
= 892.262 kg
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