Advertisements
Advertisements
Question
Give a reason for the following:
Transition metals possess a great tendency to form complex compounds.
Solution
Transition metals produce several coordination complexes for the reasons listed below:
- Transition metal ions have small sizes and a high charge density.
- The presence of vacant d-orbitals of sufficient energy that can accept lone pairs of electrons given by other groups.
APPEARS IN
RELATED QUESTIONS
In the series Sc (Z = 21) to Zn (Z = 30), the enthalpy of atomization of zinc is the lowest, i.e., 126 kJ mol−1. Why?
The `E_((M^(2+)//M))^Θ` value for copper is positive (+0.34 V). What is possibly the reason for this? (Hint: consider its high ΔaHΘ and low ΔhydHΘ)
Interstitial compounds are formed when small atoms are trapped inside the crystal lattice of metals. Which of the following is not the characteristic property of interstitial compounds?
Why first ionisation enthalpy of Cr is lower than that of Zn?
Why are fluorides of transition metals more stable in their higher oxidation state as compared to the lower oxidation state?
If enthalpies of formation of C2H4(g), CO2(g) and H2O(l) at 25°C and 1 atm pressure are 52, – 394 and – 286 kJ/mol respectively, the change in ethalpy for combustion of C2H4 is equal to
Sodium this sulphate is used in photography because of its:-
How is the variability in oxidation states of transition metals different from that of p-block elements?
Which of the following transition metals shows +1 and +2 oxidation states?
Consider the following standard electrode potential values:
\[\ce{Sn^{2+}_{ (aq)} + 2e^- -> Sn_{(s)}}\]; E0 = −0.14 V
\[\ce{Fe^{3+}_{ (aq)} + e^- -> Fe^{2+}_{ (aq)}}\]; E0 = +0.77 V
What is the cell reaction and potential for the spontaneous reaction that occurs?