English

How many distinct 5 digit numbers can be formed using the digits 3, 2, 3, 2, 4, 5 - Mathematics and Statistics

Advertisements
Advertisements

Question

How many distinct 5 digit numbers can be formed using the digits 3, 2, 3, 2, 4, 5

Sum

Solution

5 digit numbers are to be formed from 2, 3, 2, 3, 4, 5.

Case I: Numbers formed from 2, 2, 3, 4, 5 OR 2, 3, 3, 4, 5
Number of such numbers = `(5!)/(2!)xx2` = 5! = 120
Case II: Numbers formed from 2, 2, 3, 3 and any one of 4 or 5
Number of such numbers = `(5!)/(2!2!)xx2` = 60
Required number = 120 + 60 = 180
∴ 180 distinct 5 digit numbers can be formed using the digit 3, 2, 3, 2, 4, 5.

shaalaa.com
Permutations - Permutations When All Objects Are Distinct
  Is there an error in this question or solution?
Chapter 6: Permutations and Combinations - Exercise 6.4 [Page 83]

APPEARS IN

Balbharati Mathematics and Statistics 2 (Commerce) [English] 11 Standard Maharashtra State Board
Chapter 6 Permutations and Combinations
Exercise 6.4 | Q 11 | Page 83
Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×