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Question
Find the number of permutations of letters of the following word: SHANTARAM
Solution
The word SHANTARAM has 9 letters of which ‘A’ is repeated 3 times and the rest all are different.
Hence, the number of permutations
= `("n"!)/("p"!)`
= `(9!)/(3!)`
= `(9 xx 8 xx 7 xx 6 xx 5 xx 4 xx 3!)/(3!)`
= 60480
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