Advertisements
Advertisements
Question
How many orbitals are possible for n = 4?
Solution
When n = 4, l = 0, 1, 2 and 3.
Hence, there are four subshells namely, s, p, d and f
l = 0, m1 = 0; one 4s orbital.
l = 1, m = –1, 0, +1; three 4p orbitals.
l = 2, m1 = –2, –1, 0, +1, +2; five 4d orbitals.
l = 3, m1 = –3, –2, –1, 0, 1, 2, 3; seven 4f orbitals.
Hence, the number of possible orbitals when n = 4 are sixteen.
APPEARS IN
RELATED QUESTIONS
The energy of light of wavelength 45 nm is
Based on equation E = `-2.178 xx 10^(-18) "J" ("z"^2/"n"^2)`, certain conclusions are written. Which of them is not correct?
Which of the following pairs of d-orbitals will have electron density along the axes?
Two electrons occupying the same orbital are distinguished by __________.
Assertion: Number of radial and angular nodes for 3p orbital are 1, 1 respectively.
Reason: Number of radial and angular nodes depends only on principal quantum number.
The total number of orbitals associated with the principal quantum number n = 3 is
Consider the following sets of quantum numbers:
n | l | m | s | |
(i) | 3 | 0 | 0 | `+1/2` |
(ii) | 2 | 2 | 1 | `-1/2` |
(iii) | 4 | 3 | –2 | `+1/2` |
(iv) | 1 | 0 | –1 | `+1/2` |
(v) | 3 | 4 | 3 | `-1/2` |
Which of the following sets of quantum number is not possible?
Electron density in the yz plane of 3dxy orbital is
The stabilisation of a half-filled d-orbital is more pronounced than that of the p-orbital why?
Protons can be accelerated in particle accelerators. Calculate the wavelength (in Å) of such accelerated proton moving at 2.85 × 108 ms−1 (the mass of proton is 1.673 × 10−27 Kg).