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Question
How many terms are there in the series 0.5, 0.53, 0.56, ........, 1.1?
Solution
The given series is 0.5, 0.53, 0.56, ........, 1.1
0.53 – 0.5 = 0.03, 0.56 – 0.53 = 0.03, etc.
Thus, the given series is an A.P. with the first term a = 0.5 and common difference d = 0.03
Last term = l = 1.1
0.5 + (n – 1)(0.03) = 1.1
`=>` (n – 1) × 0.03 = 0.6
`=>` n – 1 = 20
`=>` n = 21
Thus, there are 21 terms in the given series.
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