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Question
How many terms are there in the series 4, 7, 10, 13, ........,148?
Solution
The given series is 4, 7, 10, 13, ........,148
7 – 4 = 3, 10 – 7 = 3, 13 – 10 = 3, etc.
Thus, the given series is an A.P. with first term a = 4 and common difference d = 3.
Last term = l = 148
4 + (n – 1)(3) = 148
`=>` (n – 1) × 3 = 144
`=>` n – 1 = 48
`=>` n = 49
Thus, there are 49 terms in the given series.
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