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Question
How many three-digit odd numbers can be formed by using the digits 0, 1, 2, 3, 4, 5? if the repetition of digits is allowed
Solution
The given digits are 0, 1, 2, 3, 4, 5
To find the possible 3-digit odd numbers.
Repetition of digits is allowed:
| Hundred's | Ten's | Unit |
The unit place can be filled in 3 ways.
We are given 6 digits.
So 10’s place can be filled in 6 ways and the 100’s place can be filled in (6 – 1)(excluding zero)5 ways
So the Number of 3 digit numbers = 3 × 6 × 5 = 90
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