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Question
If `2"x"-1/(2"x")=4`, find : `4"x"^2+1/(4"x"^2)`
Sum
Solution
`2"x"-1/"2x"=4`
`⇒(2"x"-1/"2x")^2=(4)^2`
`⇒(2"x")^2+(1/"2x")^2-2xx2"x"xx1/"2x"=16`
`⇒4"x"^2+1/"4x"^2-2=16`
`⇒4"x"^2+1/"4x"^2=16+2`
`⇒4"x"^2+1/"4x"^2=18`
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