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Question
If A is an event of a random experiment such that `"P"("A") : "P"(bar"A")` = 17 : 15 and n(S) = 640 then find n(A)
Solution
`"P"(bar"A") = 15/32`
1 − P(A) = `15/32`
⇒ ∴ P(A) = `1 - 15/32`
= `(32 - 15)/32`
= `17/32`
P(A) = `("n"("A"))/("n"("S")) = 17/32`
⇒ `("n"("A"))/640 = 17/32` ..[Given n(S) = 640]
32 n(A) = 17 × 640
n(A) = `(17 xx 640)/32`
= 17× 20
⇒ n(A) = 340
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