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If A is the arithmetic mean and G1, G2 be two geometric means between any two numbers, then prove that 2A = G12G2+G22G1 - Mathematics

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Question

If A is the arithmetic mean and G1, G2 be two geometric means between any two numbers, then prove that 2A = `(G_1^2)/(G_2) + (G_2^2)/(G_1)`

Sum

Solution

Let the two numbers be x and y

∴ A = `(x + y)/2`  ......(i)

If G1 and G2 be the geometric means between x and y then x, G1, G2, y are in G.P.

Then y = xr4-1   ....[∵ an = arn–1]

⇒ y = xr3

⇒ `y/x` = r3

⇒ r = `(y/x)^(1/3)`

Now G1 = xr

= `x(y/x)^(1/3)`   .....`[because r = (y/x)^(1/3)]`

And G2 = xr2

= `x(y/x)^(2/3)`

∴ From R.H.S. `G_1^2/G_2 + G_2^2/G_1 = (x^2(y/x)^(2/3))/(x(y/x)^(2/3)) + (x^2(y/x)^(4/3))/(x(y/x)^(1/3))`

= `x + x(y/x)^(4/3 - 1/3)`

= `x + x(y/x)`

= x + y = 2A   L.H.S.   ....[Using equation (i)]

∴ L.H.S. = R.H.S. 

Hence proved.

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Chapter 9: Sequences and Series - Exercise [Page 162]

APPEARS IN

NCERT Exemplar Mathematics [English] Class 11
Chapter 9 Sequences and Series
Exercise | Q 13 | Page 162

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