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Question
If an electron of charge (-e) and mass me revolves around the nucleus of an atom having an orbital magnetic moment m0, then the angular momentum of the electron is ______
Options
L = `(m_0e)/(2m_e)`
L = `e/(2m_0m_e)`
L = `(2m_0m_e)/e`
L = `(2e)/(m_0m_e)`
Solution
If an electron of charge (-e) and mass me revolves around the nucleus of an atom having an orbital magnetic moment m0, then the angular momentum of the electron is L = `underline((2m_0m_e)/e)`
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