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Question
If an A.P. consists of n terms with first term a and nth term l show that the sum of the mth term from the beginning and the mth term from the end is (a + l).
Solution
In the given problem, we have an A.P. which consists of n terms.
Here
The first term (a) = a
The last term (`a_n`) = 1
Now as we know
`a_n = a + (n - 1)d`
So for the mth term from the beginning, we take (n = m)
`a_m = a + (m - 1)d`
= a + md - d ......(1)
Similarly for the m th term from the end, we can take as the first term
SO we get
`a_m = l - (m -1)d`
= l - md + d ....(2)
No we need to prove `a_m + a_m' = a + l`
So adding (1) and (2) we get
`a_m + a_m = (a + md - d) + (l - md + d)`
= a + md - d + l - md + d
= a + l
Therefore `a_m + a_m' = a + l`
Hence proved
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