Advertisements
Advertisements
Question
If area of a triangular piece of cardboard is 90 cm2, then the length of altitude corresponding to 20 cm long base is ______ cm.
Solution
If area of a triangular piece of cardboard is 90 cm2, then the length of altitude corresponding to 20 cm long base is 9 cm.
Explanation:
We know that, area of triangle = `1/2` × base × height
90 = `1/2` × 20 × height
Height = 9 cm
APPEARS IN
RELATED QUESTIONS
Find the area of the triangle whose vertices are: (–5, –1), (3, –5), (5, 2)
The area of a triangle is 5. Two of its vertices are (2, 1) and (3, −2). The third vertex lies on y = x + 3. Find the third vertex.
Prove that the points A (a,0), B( 0,b) and C (1,1) are collinear, if `( 1/a+1/b) =1`.
The coordinates of the point P dividing the line segment joining the points A (1, 3) and B (4, 6) in the ratio 2 : 1 are:
Using integration, find the area of triangle ABC, whose vertices are A(2, 5), B(4, 7) and C(6, 2).
The area of a triangle with vertices (a, b + c), (b, c + a) and (c, a + b) is ______.
The area of a trapezium is 475 cm2 and the height is 19 cm. Find the lengths of its two parallel sides if one side is 4 cm greater than the other.
A rectangular plot is given for constructing a house, having a measurement of 40 m long and 15 m in the front. According to the laws, a minimum of 3 m, wide space should be left in the front and back each and 2 m wide space on each of other sides. Find the largest area where house can be constructed.
The area of a triangle with vertices A, B, C is given by ______.
Ratio of the area of ∆WXY to the area of ∆WZY is 3:4 in the given figure. If the area of ∆WXZ is 56 cm2 and WY = 8 cm, find the lengths of XY and YZ.
