Advertisements
Advertisements
Question
If k,(2k - 1) and (2k - 1) are the three successive terms of an AP, find the value of k.
Solution
It is given that k,(2k -1)and (2k +1) are the three successive terms of an AP.
∴ (2k-1) - k= (2k+1) - (2k-1)
⇒ k - 1 =2
⇒ k = 3
Hence, the value of k is 3.
APPEARS IN
RELATED QUESTIONS
In an A.P., if S5 + S7 = 167 and S10=235, then find the A.P., where Sn denotes the sum of its first n terms.
If the nth term of the A.P. 9, 7, 5, ... is same as the nth term of the A.P. 15, 12, 9, ... find n.
Find the sum of first n odd natural numbers
If the pth term of an AP is q and its qth term is p then show that its (p + q)th term is zero
The sum of the first n terms of an A.P. is 4n2 + 2n. Find the nth term of this A.P.
The sum of n terms of an A.P. is 3n2 + 5n, then 164 is its
The first three terms of an A.P. respectively are 3y − 1, 3y + 5 and 5y + 1. Then, y equals
Q.2
The sum of the first five terms of an AP and the sum of the first seven terms of the same AP is 167. If the sum of the first ten terms of this AP is 235, find the sum of its first twenty terms.
In an A.P., the sum of first n terms is `n/2 (3n + 5)`. Find the 25th term of the A.P.