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Question
If n = 6, the correct sequence for filling of electrons will be,
Options
ns → (n – 2)f → (n – 1)d → np
ns → (n – 1)d → (n – 2)f → np
ns → (n – 2)f → np → (n – 1)d
none of these are correct
Solution
ns → (n – 2)f → (n – 1)d → np
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