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Question
If p = −2, q = 1 and r = 3, find the value of 3p2q2r
Sum
Solution
Given p = −2, q = 1, r = 3
∴ 3p2q2r = 3 × (−2)2 × (1)2 × (3)
= 3 × (−2 × 1)2 × (3) ...[Since am × bm = (a × b)m]
= 3 × (−2)2 × (3)
= 3 × (−1)2 × 22 × 3
= 31+1 × 1 × 4 ...[Since am × an = am+n]
= 32 × 4
= 9 × 4
∴ 3p2q2r = 36
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