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Question
If P = {factors of 36} and Q = {factors of 48}; Find: P' ∩ Q.
Solution
1 x 36 = 36
2 x 18 = 36
3 x 12 = 36
4 x 9 = 36
6 x 6 = 36
1 x 48 = 48
2 x 24 = 48
3 x 16 = 48
4 x 12 = 48
6 x 8 = 48
∴ Factors of 36 = 1, 2, 3, 4, 6, 9, 12, 18, 36
Factors of 48 = 1, 2, 3, 4, 6, 8, 12, 16, 24, 48
P = {factors of 36}
= {1, 2, 3, 4, 6, 8, 12, 18, 36}
Q = {factors of 48}
= {1, 2, 3, 4, 6, 8, 12, 16, 24, 48}
P' ∩ Q = Only Q
= Q - P
= {1, 2, 3, 4, 6, 8, 12, 16, 24, 48} - {1, 2, 3, 4, 6, 9, 12, 18, 36}
= {8, 16, 24, 48}
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