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If the 47th division of the circular scale coincides with the zero of the main scale of a screw gauge of least count 0.01 mm and having 50 circular divisions, what is its zero error? - Physics

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Question

If the 47th division of the circular scale coincides with the zero of the main scale of a screw gauge of least count 0.01 mm and having 50 circular divisions, what is it's zero error?
Short Note

Solution

In this case, the zero error is negative
Least count of screw gauge = 0.01 mm
Thus, zero error = (50-47) X L.C.
= 3 X 0.01
= 0.03 mm

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Vernier Callipers
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Chapter 1: Measurement - Exercise 5 [Page 48]

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Frank Physics [English] Class 9 ICSE
Chapter 1 Measurement
Exercise 5 | Q 46 | Page 48
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