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A micrometre screw gauge has a negative zero error of 7 divisions. While measuring the diameter of a wire the reading on the main scale is 2 divisions - Physics

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Question

A micrometre screw gauge has a negative zero error of 7 divisions. While measuring the diameter of a wire the reading on the main scale is 2 divisions and 79th circular scale division coincides with baseline.
If the number of divisions on the main scale is 10 to a centimetre and circular scale has 100 divisions, calculate

  1. pitch
  2. observed diameter
  3. least count
  4. corrected diameter.
Numerical

Solution

(1) The number of divisions on the main scale are 10 to a centimetre

⇒ Pitch = `"Unit"/"No. of divisions in unit"=(1 "cm")/10` = 0.1 cm

(2) No. of circular scale divisions = 100

∴ Least count (L.C.) = `"Pitch"/"No. of circular scale divisions"`

= `0.1/100` cm

= 0.001 cm

(3) Main scale reading = 2 division
⇒ Main scale reading = 2 × Pitch = 0.2 cm
Circular scale reading = 79 division
∴ Observed diametre = M.S. reading + L.C. × C.S. reading
= 0.2 + 0.001 × 79
= 0.2 + 0.079 cm
= 0.279 cm

(4) Negative zero error = 7 division
∴ Correct = −(−7 × L.C.)
= −(−7 × 0.001) cm
= +0.007 cm
Correct diametre = Observed diametre + Correction
= 0.279 + 0.007
= 0.286 cm

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Vernier Callipers
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Chapter 1: Measurements and Experimentation - Unit 4 Practice Problems 4

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Goyal Brothers Prakashan A New Approach to ICSE Physics Part 1 [English] Class 9
Chapter 1 Measurements and Experimentation
Unit 4 Practice Problems 4 | Q 2
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