Question

If the concentration of glucose $$(\mathrm{C}{\phantom{A}}_6\mathrm{H}{\phantom{A}}_{12}\mathrm{O}{\phantom{A}}_6)$$ in blood is 0.9 g L^–1, what will be the molarity of glucose in blood?

Options

• 5 M

• 50 M

• 0.005 M

• 0.5 M

Answer 1

0.005 M

Explanation:

Molar mass of glucose $$(\mathrm{C}{\phantom{A}}_6\mathrm{H}{\phantom{A}}_{12}\mathrm{O}{\phantom{A}}_6)$$

= 12 × 6 + 1 × 12 + 16 × 6 = 180

Molarity = ${\displaystyle \frac{{\text{conc. in gL}}^{-1}}{\text{Molar mass}}=\frac{0.90 {\text{gL}}^{-1}}{180 {\text{g mol}}^{-1}}}$ = 0.005 M