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Question
If two coins are tossed, find the probability of the following event.
Getting at least one head.
Sum
Solution
Sample Space (S) = {HH, HT, TT, TH}
∴ n(S) = 4
Event A: Getting at least one head
A = {HH, HT, TH}
∴ n(A) = 3
therefore P(A) = `(n(A))/(n(S))`
= `3/4`
Hence, the probability of getting at least one head is `3/4`.
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