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Question
If y = (tan-1 x)2, show that
`(1+x^2)^2(d^2y)/dx^2+2x(1+x^2)dy/dx-2=0`
Sum
Solution
y = tan -1x
y1 = `1/(1+"x"^2)`
y2 = `(d(1+x^2)^(-1))/"dx" = -1/(1+x^2)^2 xx ("2x")`
y2 = `(-2x)/(1+x^2)^2`
y2 (1+x2) = -2x `(1/(1+x^2))`
y2 (1+x2) = -2 xy1
y2 (1+x2) + 2xy1 = 0
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