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Question
In a chemistry lab, there is some quantity of 50% acid solution and some quantity of 25% acid solution. How much of each should be mixed to make 10 litres of 40% acid solution?
Sum
Solution
Let taking x litres quantity of 50% acid solution
and y litres quantity of 25% acid solution.
Given, After mixing both types of acid.
Solution, The total quantity is 10 litres.
Therefore, x + y = 10 ...(i)
According to the question,
`50/100x + 25/100y = 40/100 xx 10`
⇒ `x/2 + y/2 = 4`
2x + y = 16 ...(ii)
On subtracting eq. (i) from eq. (ii)
x = 6 litres
Put x = 6 in eq. (i) to get y
6 + y = 10
y = 10 − 6
⇒ y = 4 litres
Hence, we should take 6 litres from 50% Acid solution and 4 litres from 25% Acid solution.
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