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Question
In a cricket match, a batsman hits a boundary 12 times out of 80 balls he plays, further, if he plays one ball more, what will be the probability that:
(i) he hits a boundary
(ii) he does not hit a boundary
Solution
(i) Total number of balls = 80
Hits boundaries = 12 times
∴ P (Hitting a boundary) = `12/80=3/20`
(ii) P (of not hitting a boundary) = `68/80=17/20`
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