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Question
A box contains 3 yellow, 4 green, and 8 blue tickets. A ticket is chosen at random. Find the probability that the ticket is:
(i) yellow
(ii) green
(iii) blue
(iv) red
(v) not yellow
Solution
Number of yellow tickets = 3
Number of green tickets = 4
Number of blue tickets = 3 + 4 + 8 = 15
(i) P (getting a yellow ticket) =`3/15=1/5`
(ii) P (getting a green ticket) =`4/15`
(iii) P (getting a blue ticket) =`8/15`
(iv) Since, Basket contains yellow, green and blue tickets only.
∴ Number or red tickets = 0
∴ P (getting an red ticket) =`0/15=0`
(v) Total number of green and blue tickets = 4 + 8 = 12 tickets
P (not getting yellow ticket) = P(getting either green or blue ticket) =`12/15=4/5`
OR
P (not getting a yellow ticket) =`1-1/5=(5-1)/5=4/5`
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