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Question
In a single throw of two dice, find the probability of a doublet.
Solution
The number of possible outcomes is 6 × 6 = 36.
We write them as given below:
1, 11, 21, 31, 41, 51, 6
2, 12, 22, 32, 42, 52, 6
3, 13, 23, 33, 43, 53, 6
4, 14, 24, 34, 44, 54, 6
5, 15, 25, 35, 45, 55, 6
6, 16, 26, 36, 46, 56, 6
n(S) = 36
E = Event of getting a doublet
= {(1, 1),(2, 2),(3, 3),(4, 4),(5, 5),(6, 6)}
n(E) = 6
Probability of getting a doublet = `(n(E))/(n(S)) = 6/36 = 1/6`
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