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Question
In a ‘tree plantation’ project of a certain school there are 45 students of 'Harit Sena'. The record of trees planted by each student is given below:
3, 5, 7, 6, 4, 3, 5, 4, 3, 5, 4, 7, 5, 3, 6, 6, 5, 3, 4, 5, 7, 3, 5, 6, 4, 4, 3, 5, 6, 6, 4, 3, 5, 7, 3, 4, 5, 7, 6, 4, 3, 5, 4, 4, 7.
Prepare a frequency distribution table of the data.
Solution
The record of trees planted by each student is given below:
3, 5, 7, 6, 4, 3, 5, 4, 3, 5, 4, 7, 5, 3, 6, 6, 5, 3, 4, 5, 7, 3, 5, 6, 4, 4, 3, 5, 6, 6, 4, 3, 5, 7, 3, 4, 5, 7, 6, 4, 3, 5, 4, 4, 7.
The frequency distribution table of the given data is as follows:
| Number of trees planted | Tally marks | Number of students/Frequency |
| 3 | `cancel(bb|bb|bb|bb|)` `cancel(bb|bb|bb|bb|)` | 10 |
| 4 | `cancel(bb|bb|bb|bb|)` `cancel(bb|bb|bb|bb|)` `bb|` | 11 |
| 5 | `cancel(bb|bb|bb|bb|)` `cancel(bb|bb|bb|bb|)` `bb|` | 11 |
| 6 | `cancel(bb|bb|bb|bb|)` `bb||` | 7 |
| 7 | `cancel(bb|bb|bb|bb|)` `bb|` | 6 |
| Total | N = 45 |
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| Weights (in kg.) |
Tally Marks | Frequency (Number of persons) |
| 40 – 50 | `\cancel(bb|bb|bb|bb|) \cancel(bb|bb|bb|bb|) bb|bb|` | |
| 50 – 60 | `\cancel(bb|bb|bb|bb|) \cancel(bb|bb|bb|bb|) bb|bb|bb|bb|` | |
| 60 – 70 | `\cancel(bb|bb|bb|bb|) bb|` | |
| 70 – 80 | `bb|bb|` | |
| 80 – 90 | `bb|` |
Find the total number of persons whose weights are given in the above table.
