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Question
In a two digit number, digit at the ten's place is twice the digit at units's place. If the number obtained by interchanging the digits is added to the original number, the sum is 66. find the number.
Solution
Let the digit at the unit's place be x.
Digit at tens place = 2x
Original number = (2x)×10 + x = 21x
Number obtained by interchanging the digits = (x) × 10 + 2x = 12x
From the given information,
12x + 21x = 66
33x = 66
x = 2
∴ The unit's digit = 2.
∴ Original number = 21 × 2 = 42.
Hence, the original number is 42.
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