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Question
In ∆ABC, if m∠A = `(7pi^"c")/36`, m∠B = 120°, find m∠C in degree and radian.
Solution
We know that θc = `(theta xx 180/pi)^circ`
In ∆ABC,
m∠A = `(7pi^"c")/36`
= `((7pi)/36 xx 180/pi)^circ`
= 35°,
m∠B = 120°
∴ m∠A + m∠B + m∠C = 180° ...[Sum of the angles of a triangle is 180°]
∴ 35° + 120° + m∠C = 180°
∴ m∠C = 180° – 35° – 120°
∴ m∠C = 25°
= `(25 xx pi/180)^"c" ...[because theta^circ = (theta xx pi/180)^"c"]`
= `((5pi)/36)^"c"`
∴ m∠C = 25°
= `((5pi)/36)^"c"`
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