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Question
In an isosceles triangle, the base angles are equal. The vertex angle is 40°. What are the base angles of the triangle? (Remember, the sum of three angles of a triangle is 180°).
Solution
Let the base angles be equal to b.
The sum of all interior angles of a triangle is 180°.
b + b + 40° = 180°
2b + 40° = 180°
2b = 180° - 40°
b = 140° ...(Transposing 40° to R.H.S.)
Dividing both sides by 2,
`(2b)/2 = (140°)/2`
b = 70°
Therefore, the base angles of the triangle are of 70°.
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