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Question
In a biprism experiment, a slit is illuminated by a light of wavelength 4800 Å The distance between the slit and biprism is 15 cm and the distance between the biprism and eyepiece is 85 cm. If the distance between virtual sources is 3 mm, determine the distance between 4th bright band on one side and 4th dark band on the other side of the central bright band.
Solution
λ = 4800 Å = 4.8 × 10−7m,
d = 3 mm = 3 × 10−3m,
D = 15 + 85 = 100 cm = 1 m
Distance between 4th bright band on one side and 4th dark band on the other side of the central
bright band, (X4 + X′4) = ?
For nth bright band,
The distance between 4th bright band on one side and 4th dark band on the other side of the central bright band is 12 × 10−4 m.
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