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Question
In each of the following, determine whether the given values are solution of the given equation or not:
x2 + x + 1 = 0; x = 0; x = 1
Solution
Now Substitute x = 0 in given equation
L.H.S. = (0)2 + 0 + 1 ≠ 0 ≠ R.H.S.
on substituting x = 1 in L.H.S. of given equation
⇒ (1)2 + 1 + 1 ≠ 0 ≠ R.H.S.
Hence x = 0 and x = 1 are not solutions of the given equation.
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