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Question
At t minutes past 2 pm, the time needed by the minutes hand of a clock to show 3 pm was found to be 3 minutes less than `t^2/4` minutes. Find t.
Solution
We know that, the time between 2 pm to 3 pm = 1 h = 60 min
Given that, at f min past 2 pm, the time needed by the minute hand of a clock to show 3 pm was found to be 3 min less than `t^2/4` min
i.e., `t + (t^2/4 - 3)` = 60
⇒ 4t + t2 – 12 = 240
⇒ t2 + 4t – 252 = 0
⇒ t2 + 18t – 14t – 252 = 0 .....[By splitting the middle term]
⇒ t(t + 18) – 14(t + 18) = 0 ....[Since, time cannot be negative, so t ≠ – 18]
⇒ (t + 18)(t – 14) = 0
∴ t = 14 min
Hence, the required value of t is 14 min.
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