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Question
In the following, find the coordinates of the point whose abscissa is the solution of the first equation and ordinate is the solution of the second equation:
3 - 2x = 7; 2y + 1 = 10 - 2`(1)/(2)`y.
Solution
3 - 2x = 7; 2y + 1 = 10 - 2`(1)/(2)`y
Now
3 - 2x = 7
3 - 7 = 2x
-4 = 2x
-2 = x
Again
2y + 1 = 10 - 2`(1)/(2)`y
2y + 1 = 10 -`(5)/(2)`y
4y + 2 = 20 - 5y
4y + 5y = 20 - 2
9y = 18
y = 2
∴ The co-ordinates of the point (-2, 2)
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In each of the following, find the coordinates of the point whose abscissa is the solution of the first equation and ordinate is the solution of the second equation.
5 + 2x = `9: 3(1)/(2)y + 1` = 12 - 3y
In each of the following, find the coordinates of the point whose abscissa is the solution of the first equation and ordinate is the solution of the second equation.
(7 - x) + 7x = `(x + 5); (2 + 3y)/(2)` = 2y - 6
