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Question
In an examination the ratio of the number of suo:essful candidates to unsuccessful candidates is 7:5. Had 30 more appeared and 10 more passed, the ratio of successful candidates to unsuccessful candidates would have been 4:3. Find the number of candidates who appeared in the examination originally.
Solution
Let successful candidates be 7x and unsuccessful candidates be 5x.
Now , `(7"x" + 10)/(5"x" + 20) = 4/3`
⇒ 21x + 30 = 20x + 80
⇒ x = 50
7x = 7 x 50 = 350
5x = 5x50 = 250
.·. 7x + 5x = 350 + 250 = 600
Therefore, there were 600 candidates originally.
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