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Maharashtra State BoardSSC (English Medium) 8th Standard

In the example given below, the radius of the base of a cylinder and its height is given. Then find the curved surface area and total surface area. r = 1.4 cm, h = 2.1 cm - Marathi (Second Language) [मराठी (द्वितीय भाषा)]

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Question

In the example given below, the radius of the base of a cylinder and its height is given. Then find the curved surface area and total surface area.

r = 1.4 cm, h = 2.1 cm

Sum

Solution

Given: r = 1.4 cm and h = 2.1 cm

Curved surface area of cylinder and total surface area
Curved surface area of the cylinder = 2πrh

= `2 xx 22/7 xx 1.4 xx 2.1`

= `2 xx 22 xx 0.2 xx 2.1`

= 18.48 sq. cm

Total surface area of the cylinder = 2πr (h + r)

= `2 xx 22/7 xx 1.4(2.1 + 1.4)`

= `2 xx 22/7 xx 1.4 xx 3.5`

= `2 xx 22 xx 0.2 3.5`

= `30.80` sq. cm

∴ The curved surface area of the cylinder is 18.48 sq. cm and its total surface area is 30.80 sq. cm.

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Chapter 16: Surface area and Volume - Practice Set 16.2 [Page 110]

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Balbharati Mathematics [English] 8 Standard Maharashtra State Board
Chapter 16 Surface area and Volume
Practice Set 16.2 | Q 1. (2) | Page 110
Balbharati Integrated 8 Standard Part 4 [English Medium] Maharashtra State Board
Chapter 3.3 Surface Area and Volume
Practice Set 16.2 | Q 1. (2) | Page 65
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