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Question
In the figure, quadrilateral ABCD is a cyclic. If ∠DAB = 75°, then find measure of ∠DCB.
Sum
Solution
In ▢ABCD,
∠DAB = 75° .....[Given]
∠DAB + ∠DCB = 180° ......[Opposite angle of cyclic quadrilateral are supplementary]
∴ 75° + ∠ DCB = 180°
∴ ∠ DCB = 180° – 75°
∴ ∠ DCB = 105°
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Corollary of Cyclic Quadrilateral Theorem
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