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Question
In the adjoining figure, seg DE is the chord of the circle with center C. seg CF⊥ seg DE and DE = 16 cm, then find the length of DF?
Solution
In given figure, seg CF ⊥ Chord DE
∴ DF ≅ DE ......[[A perpendicular drawn from the centre of a circle on its chord bisects the chord]
∴ DF = `1/2` DE
= `1/2 xx 16` .....[Given]
∴ DF = 8 cm
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