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Question
From an external point P, tangents PA and PB are drawn to the circle with centre O. If CD is the tangent to the circle at point E and PA = 14 cm. Find the perimeter of ABCD.
Solution
PA = 14 cm
Perimeter of ΔPCD = PC + PD + CD = PC + PD + CE + ED
We know that
The two tangents drawn from external point to the circle are equal in length.
From point P, PA = PB = 14cm
From point C, CE = CA
From point D, DB = ED
Perimeter = PC + PD + CA +DB
= (PC + CA) + (PD + DB)
= PA + PB = 14 + 14 = 28 cm.
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