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Question
In figure, AB is a chord of the circle and AOC is its diameter such that ∠ACB = 50°. If AT is the tangent to the circle at point A, then ∠BAT is equal to ______.
Options
65°
60°
50°
40°
Solution
In figure, AB is a chord of the circle and AOC is its diameter such that ∠ACB = 50°. If AT is the tangent to the circle at point A, then ∠BAT is equal to 50°.
Explanation:
In figure, AOC is a diameter of the circle.
We know that, diameter subtends an angle 90° at the circle.
So, ∠ABC = 90°
In ΔACB,
∠A + ∠B + ∠C = 180° ...[Since, sum of all angles of a triangle is 180°]
⇒ ∠A + 90° + 50° = 180°
⇒ ∠A + 140° = 180°
⇒ ∠A = 180° – 140° = 40°
∠A or ∠OAB = 40°
Now, AT is the tangent to the circle at point A.
So, OA is perpendicular to AT.
∴ ∠OAT = 90° ...[From figure]
⇒ ∠OAB + ∠BAT = 90°
On putting ∠OAB = 40°, we get
⇒ ∠BAT = 90° – 40° = 50°
Hence, the value of ∠BAT is 50°.
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