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In the adjoining figure, seg DE is the chord of the circle with center C. seg CF⊥ seg DE and DE = 16 cm, then find the length of DF? - Geometry Mathematics 2

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प्रश्न

In the adjoining figure, seg DE is the chord of the circle with center C. seg CF⊥ seg DE and DE = 16 cm, then find the length of DF?

योग

उत्तर

In given figure, seg CF ⊥ Chord DE

∴ DF ≅ DE      ......[[A perpendicular drawn from the centre of a circle on its chord bisects the chord]

∴ DF = `1/2` DE

= `1/2 xx 16`   .....[Given]

∴ DF = 8 cm

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