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Question
If from any point on the common chord of two intersecting circles, tangents be drawn to circles, prove that they are equal.
Solution
Let the two circles intersect at points X and Y.
XY is the common chord.
Suppose ‘A’ is a point on the common chord and AM and AN be the tangents drawn A to the circle
We need to show that AM = AN.
In order to prove the above relation, following property will be used.
“Let PT be a tangent to the circle from an external point P and a secant to the circle through
P intersects the circle at points A and B, then ๐๐2 = ๐๐ด × ๐๐ต"
Now AM is the tangent and AXY is a secant ∴ ๐ด๐2 = ๐ด๐ × ๐ด๐ … . . (๐)
AN is a tangent and AXY is a secant ∴ ๐ด๐2 = ๐ด๐ × ๐ด๐ … . . (๐๐)
From (i) & (ii), we have ๐ด๐2 = ๐ด๐2
∴ AM = AN
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